俗話說：工欲善其事必先利其器。很多參加了新版gre考試的同學(xué)都覺得數(shù)學(xué)有點難度，相信這其中的原因還是由于考生在新版gre數(shù)學(xué)復(fù)習(xí)時沒有把基礎(chǔ)打牢。如果新版gre數(shù)學(xué)基本考點都沒有復(fù)習(xí)到，如何能拿到分?jǐn)?shù)呢?所以說，想要新版gre數(shù)學(xué)考好，復(fù)習(xí)的時候一定要把基本概念和重要考點都弄扎實。

　　今天針對新版gre數(shù)學(xué)復(fù)習(xí)，小編給大家整理的是關(guān)于Combinations of Choices的相關(guān)內(nèi)容，這些概念在考試中一定會考到的。希望考生能再接再厲，取得一個好成績，突破新版gre數(shù)學(xué)難的困境。

　　新版gre數(shù)學(xué)復(fù)習(xí)重要考點：Permutation of Objects

　　The number of ways n distinct objects can be ordered is n!.

　　Example:

　　Number of ways 6 people can from a queue is 6!.

　　Number of ways 5 different cars can be parked in 5 parking spaces is 5!.

　　Remember:

　　This does not apply if there are identical objects or ordering does not matter.

　　新版gre數(shù)學(xué)復(fù)習(xí)重要考點：Permutation with Selection

　　The number of ways n objects drawn from a collection of m distinct objects can be ordered is m!/!.

　　Example:

　　Number of ways a queue of length 3 can be formed from a group of 5 people is 5!/!=5!/2!=543=60.

　　Number of possible top ten list for 150 movies is 150!/!.

　　Remember:

　　This does not apply if there are identical objects or ordering does not matter.

　　俗話說：工欲善其事必先利其器。很多參加了新版gre考試的同學(xué)都覺得數(shù)學(xué)有點難度，相信這其中的原因還是由于考生在新版gre數(shù)學(xué)復(fù)習(xí)時沒有把基礎(chǔ)打牢。如果新版gre數(shù)學(xué)基本考點都沒有復(fù)習(xí)到，如何能拿到分?jǐn)?shù)呢?所以說，想要新版gre數(shù)學(xué)考好，復(fù)習(xí)的時候一定要把基本概念和重要考點都弄扎實。

　　今天針對新版gre數(shù)學(xué)復(fù)習(xí)，小編給大家整理的是關(guān)于Combinations of Choices的相關(guān)內(nèi)容，這些概念在考試中一定會考到的。希望考生能再接再厲，取得一個好成績，突破新版gre數(shù)學(xué)難的困境。

　　新版gre數(shù)學(xué)復(fù)習(xí)重要考點：Permutation of Objects

　　The number of ways n distinct objects can be ordered is n!.

　　Example:

　　Number of ways 6 people can from a queue is 6!.

　　Number of ways 5 different cars can be parked in 5 parking spaces is 5!.

　　Remember:

　　This does not apply if there are identical objects or ordering does not matter.

　　新版gre數(shù)學(xué)復(fù)習(xí)重要考點：Permutation with Selection

　　The number of ways n objects drawn from a collection of m distinct objects can be ordered is m!/!.

　　Example:

　　Number of ways a queue of length 3 can be formed from a group of 5 people is 5!/!=5!/2!=543=60.

　　Number of possible top ten list for 150 movies is 150!/!.

　　Remember:

　　This does not apply if there are identical objects or ordering does not matter.