久久一区二区三区精品-久久一区二区明星换脸-久久一区二区精品-久久一区不卡中文字幕-91精品国产爱久久久久久-91精品国产福利尤物免费

考試輔導:GMAT數學精解--算術概述

雕龍文庫 分享 時間: 收藏本文

考試輔導:GMAT數學精解--算術概述

  1.平均數

  2.中數

  To calculate the median of n numbers,first order the numbers from least to greatest;if n is odd,the median is defined as the middle number,while if n is even,the median is defined as the average of the two middle numbers. For the data 6, 4, 7, 10, 4, the numbers, in order, are 4, 4, 6, 7, 10, and the median is 6, the middle number. For the numbers 4, 6, 6, 8, 9, 12, the median is /2 = 7. Note that the mean of these numbers is 7.5.

  3.眾數:一組數中的眾數是指出現頻率最高的數。

  例:the mode of 7,9,6,7,2,1 is 7。

  4.值域:表明數的分布的量,其被定義為最大值減最小值的差。

  例:the range of1,7,27,27,36 is 36-= 37。

  5.標準方差:

  One of the most common measures of dispersion is the standard deviation. Generally speaking, the greater the data are spread away from the mean, the greater the standard deviation. The standard deviation of n numbers can be calculated as follows:

  find the arithmetic mean ;

  find the differences between the mean and each of the n numbers ;

  square each of the differences ;

  find the average of the squared differences ;

  take the nonnegative square root of this average.

  Notice that the standard deviation depends on every data value, although it depends most on values that are farthest from the mean. This is why a distribution with data grouped closely around the mean will have a smaller standard deviation than data spread far from the mean.

  6.排列與組合

  There are some useful methods for counting objects and sets of objects without actually listing the elements to be counted. The following principle of Multiplication is fundamental to these methods.

  If a first object may be chosen in m ways and a second object may be chosen in n ways, then there are mn ways of choosing both objects.

  As an example, suppose the objects are items on a menu. If a meal consists of one entree and one dessert and there are 5 entrees and 3 desserts on the menu, then 53 = 15 different meals can be ordered from the menu. As another example, each time a coin is flipped, there are two possible outcomes, heads and tails. If an experiment consists of 8 consecutive coin flips, the experiment has 28 possible outcomes, where each of these outcomes is a list of heads and tails in some order.

  階乘:factorial notation

  假如一個大于1的整數n,計算n的階乘被表示為n!,被定義為從1至n所有整數的乘積,

  例如:4! = 4321= 24

  

  排列:permutations

  The factorial is useful for counting the number of ways that a set of objects can be ordered. If a set of n objects is to be ordered from 1st to nth, there are n choices for the 1st object, n-1 choices for the 2nd object, n-2 choices for the 3rd object, and so on, until there is only 1 choice for the nth object. Thus, by the multiplication principle, the number of ways of ordering the n objects is

  n = n!

  For example, the number of ways of ordering the letters A, B, and C is 3!, or 6:ABC, ACB, BAC, BCA, CAB, and CBA.

  These orderings are called the permutations of the letters A, B, and C.也可以用P 33表示.

  Pkn = n!/ !

  例如:1, 2, 3, 4, 5這5個數字構成不同的5位數的總數為5! = 120

  組合:combination

  A permutation can be thought of as a selection process in which objects are selected one by one in a certain order. If the order of selection is not relevant and only k objects are to be selected from a larger set of n objects, a different counting method is employed.

  Specially consider a set of n objects from which a complete selection of k objects is to be made without regard to order, where 0n . Then the number of possible complete selections of k objects is called the number of combinations of n objects taken k at a time and is Ckn.

  從n個元素中任選k個元素的數目為:

  Ckn. = n!/ ! k!

  例如:從5個不同元素中任選2個的組合為C25 = 5!/2! 3!= 10

  排列組合的一些特性

  加法原則:Rule of Addition

  做某件事有x種方法,每種方法中又有各種不同的解決方法。例如第一種方法中有y1種方法,第二種方法有y2種方法,等等,第x種方法中又有yx種不同的方法,每一種均可完成這件事,即它們之間的關系用or表達,那么一般使用加法原則,即有:y1+ y2+。。。+ yx種方法。

  乘法原則:Rule of Multiplication

  完成一件事有x個步驟,第一步有y1種方法,第二步有y2種方法,。。。,第x步有yx種方法,完成這件事一共有y1 y2 。。。 yx種方法。

  以上只是GMAT考題中經常涉及到的數學算術方面的問題,今后我們將陸續在新開辟的網上課堂中介紹代數、幾何以及系統的習題、講解,以幫助大家在GMAT數學考試中更好地發揮中國學生的優勢,拿到讓美國人瞠目結舌的成績!

  

  1.平均數

  2.中數

  To calculate the median of n numbers,first order the numbers from least to greatest;if n is odd,the median is defined as the middle number,while if n is even,the median is defined as the average of the two middle numbers. For the data 6, 4, 7, 10, 4, the numbers, in order, are 4, 4, 6, 7, 10, and the median is 6, the middle number. For the numbers 4, 6, 6, 8, 9, 12, the median is /2 = 7. Note that the mean of these numbers is 7.5.

  3.眾數:一組數中的眾數是指出現頻率最高的數。

  例:the mode of 7,9,6,7,2,1 is 7。

  4.值域:表明數的分布的量,其被定義為最大值減最小值的差。

  例:the range of1,7,27,27,36 is 36-= 37。

  5.標準方差:

  One of the most common measures of dispersion is the standard deviation. Generally speaking, the greater the data are spread away from the mean, the greater the standard deviation. The standard deviation of n numbers can be calculated as follows:

  find the arithmetic mean ;

  find the differences between the mean and each of the n numbers ;

  square each of the differences ;

  find the average of the squared differences ;

  take the nonnegative square root of this average.

  Notice that the standard deviation depends on every data value, although it depends most on values that are farthest from the mean. This is why a distribution with data grouped closely around the mean will have a smaller standard deviation than data spread far from the mean.

  6.排列與組合

  There are some useful methods for counting objects and sets of objects without actually listing the elements to be counted. The following principle of Multiplication is fundamental to these methods.

  If a first object may be chosen in m ways and a second object may be chosen in n ways, then there are mn ways of choosing both objects.

  As an example, suppose the objects are items on a menu. If a meal consists of one entree and one dessert and there are 5 entrees and 3 desserts on the menu, then 53 = 15 different meals can be ordered from the menu. As another example, each time a coin is flipped, there are two possible outcomes, heads and tails. If an experiment consists of 8 consecutive coin flips, the experiment has 28 possible outcomes, where each of these outcomes is a list of heads and tails in some order.

  階乘:factorial notation

  假如一個大于1的整數n,計算n的階乘被表示為n!,被定義為從1至n所有整數的乘積,

  例如:4! = 4321= 24

  

  排列:permutations

  The factorial is useful for counting the number of ways that a set of objects can be ordered. If a set of n objects is to be ordered from 1st to nth, there are n choices for the 1st object, n-1 choices for the 2nd object, n-2 choices for the 3rd object, and so on, until there is only 1 choice for the nth object. Thus, by the multiplication principle, the number of ways of ordering the n objects is

  n = n!

  For example, the number of ways of ordering the letters A, B, and C is 3!, or 6:ABC, ACB, BAC, BCA, CAB, and CBA.

  These orderings are called the permutations of the letters A, B, and C.也可以用P 33表示.

  Pkn = n!/ !

  例如:1, 2, 3, 4, 5這5個數字構成不同的5位數的總數為5! = 120

  組合:combination

  A permutation can be thought of as a selection process in which objects are selected one by one in a certain order. If the order of selection is not relevant and only k objects are to be selected from a larger set of n objects, a different counting method is employed.

  Specially consider a set of n objects from which a complete selection of k objects is to be made without regard to order, where 0n . Then the number of possible complete selections of k objects is called the number of combinations of n objects taken k at a time and is Ckn.

  從n個元素中任選k個元素的數目為:

  Ckn. = n!/ ! k!

  例如:從5個不同元素中任選2個的組合為C25 = 5!/2! 3!= 10

  排列組合的一些特性

  加法原則:Rule of Addition

  做某件事有x種方法,每種方法中又有各種不同的解決方法。例如第一種方法中有y1種方法,第二種方法有y2種方法,等等,第x種方法中又有yx種不同的方法,每一種均可完成這件事,即它們之間的關系用or表達,那么一般使用加法原則,即有:y1+ y2+。。。+ yx種方法。

  乘法原則:Rule of Multiplication

  完成一件事有x個步驟,第一步有y1種方法,第二步有y2種方法,。。。,第x步有yx種方法,完成這件事一共有y1 y2 。。。 yx種方法。

  以上只是GMAT考題中經常涉及到的數學算術方面的問題,今后我們將陸續在新開辟的網上課堂中介紹代數、幾何以及系統的習題、講解,以幫助大家在GMAT數學考試中更好地發揮中國學生的優勢,拿到讓美國人瞠目結舌的成績!

  

主站蜘蛛池模板: 免费福利入口在线观看 | 亚洲精品a| 狠狠色丁香久久婷婷综合_中 | 成人看的午夜免费毛片 | 成人合成mv福利视频网站 | 99精品在线免费 | 综合亚洲一区二区三区 | 亚洲国产综合久久精品 | 国产精品成人在线播放 | 国产主播精品福利19禁vip | 国产亚洲高清在线精品不卡 | 亚洲国产成人在线 | 男人的亚洲天堂 | 亚洲欧美第一 | 国产高清在线精品二区一 | 男人的天堂免费网站 | 亚洲国产精品一区二区九九 | 91精品国产综合成人 | 精品一区二区三区中文 | 成人国产精品一级毛片天堂 | 免费一级美国片在线观看 | 久久成人免费播放网站 | 成人免费在线网站 | 国产成人午夜精品免费视频 | 欧美高清一区二区三区欧美 | 久久久久久久99视频 | 在线高清免费爱做网 | 欧美一区二区三区在线观看 | 国产在线日韩 | 欧美一级毛片怡红院 | 亚洲另类激情综合偷自拍 | 国产精品李雅在线观看 | 精品三级内地国产在线观看 | 国产精品短视频免费观看 | 国产欧美精品一区二区 | 国产精品免费大片一区二区 | 性色综合 | 欧美成人免费网在线观看 | 成人在线免费观看 | 在线精品国产成人综合第一页 | 欧美成人a人片 |